Ohm's Law is one of the most useful formulas you will ever learn, It is
the most basic law of current flow and is named after it's discoverer
Georg Ohm. his law states that the amount of current flowing in a
circuit made up of pure resistances is directly proportional to the
electromotive force impressed on a circuit and is inversely
proportional to the total resistance of the circuit. In English what
he is saying is that the amount of current flowing through a circuit
is directly proportional to the voltage being applied to the circuit
and inversely proportional to the amount of resistance in the
circuit. What does all that mean, if we increase the voltage
in a given circuit and the resistance stays the same the current will
increase, or if the voltage is the same and we increase the resistance
the current will drop.

E = Voltage also known as E in E= I x R
I = Current also known as A or amps
R= Resistance also known as ohms
Ohms law can be applied to both AC and DC circuits but due to the
complexity of AC and invoking inductances and capacitances I will speak
directly about DC as this will give you the most basic understanding.
DC
or direct current is current that flows in one direction. I would like
you to think of it as water flowing through a hose . Voltage
will be the city water pressure and the resistance will be the spray
nozzle at the end of the hose. If the water pressure is a constant
60lbs and we hold the hose nozzle fully open so that there is little or
no resistance to flow a large amount of water will flow through the hose
. Now if everyone on the street turned their water on and the city water
pressure dropped to 30lbs the amount of water flowing through the hose
would be far less, so before our water would shoot 20 feet out of the
end of the hose, now it only shoots 10 feet (current was reduced). If we go back to the
60lbs water pressure and only hold the nozzle open half way the result would
be the same we would only spray 10 feet but yet our pressure is still
60lbs WHY ? we increased the resistance to flow and therefore
reduced the amount of water flowing . Now lets put that to a DC circuit.
Jim has an idea so he takes the 12 volt battery out of his
boat and hooks it up to a control circuit. When everything is connected
he puts his amp meter in the circuit and he gets a reading of 6 amps.
How does Jim find out how much resistance the circuit has ?.
E = I x R
E = 12 volts, I = 6 amps & R = X
or
12 = 6 x R
R = 12/6
R = 2 ohms
In this example if we were to double the voltage to 24 volts what
would our resistance be ?
R = 4 ohms

Look at the figure above and answer the following.
- 6V power supply and we add a light bulb with a resistance of
4 ohms what will our current be ?
- 12V power supply and we measure a current reading of 8 amps what's
our resistance ?
- 24V power supply and a relay with a resistance of 6 ohms what's
the current going to be ?
- 36V power supply and a current draw of 10 A what the resistance.
- No picture this time :) we have a heater with a resistance
of 8 ohms and the power requirements on the name plate say 120 V
what will the current draw be ?
Answers : 1- 1.5A 2- 1.5 ohms 3- 4 amps 4-
3.6 ohms 5- 15 amps
TYPES OF CIRCUITS
These circuits have both series and parallel branches in them , they
are more complicated but we can easily work through them.

The best way to solve this problem is to break it apart into smaller
ones. We have parallel branches here and each branch has 2 resistors in
series with each other . To begin lets first combine the series
resistors so all we will have left is 3 branches.
Path A = 3 + 4 = 7 ohms
Path B = 6 + 7= 13 ohms
Path C = 10 + 1 = 11 ohms
As you can see now all we have to worry about is the parallel part .
1/R total = 1/7 + 1/13 + 1/11 = 311 / 1001
R total = 311 /1001 ( 3.219 )
WHAT ? if you've just shouted this out no problem we will work out the
math. If you got this answer right just skip to the next section on
Power by Clicking here.

Our first parallel circuit was quite easy to solve with the numbers I
used.
Our resistance were 2ohms, 4 ohms, & 8 ohms if
we divide these by 1 as the formula suggests we come up with .
1/2 + 1/4 + 1/8 = 7/8 we were able to work it out in our head because
both 2,4 & 8 all divide evenly into 8.
or 1/2 = 4/8, 1/4 = 2/8, 1/8 = 1/8, 4/8 + 2/8 + 1/8
= 7/8 and when we divided 7 into 8 our answer was 1.14 ohms
This second problem seams far more confusing since how did we ever
get 311/1001 ?
What we have to do is find a number that all the numbers we have divide
into equally. Lets review our problem.
- Path A = 3 + 4 = 7 ohms
Path B = 6 + 7= 13 ohms
Path C = 10 + 1 = 11 ohms
2. Apply the formula

1/7 + 1/13 + 1/11 = 311 /
1001
1001 is a number that 7, 13, & 11 all divide into equally.
How did I get this number ?
7 x 13 x 11 = 1001 Ok that's easy but where does the 311
come from ?
Once you have the 1001 you divide the numbers into it.
7/1001 = 143, 13/1001 = 77 , 11 / 1001 =
91 143 + 77 + 91 = 311
311/1001 = 3.219 ohms
Lets now review the first problem.
1/2 + 1/4 + 1/8 = 7/8
2 x 4 x 8 = 64
2/64 = 32 , 4/64 = 16, 8 /64 = 8
32 + 16 + 8 =56
56/64 or 7/8 when broken down
7/8 = 1.143
Congratulation's you've got it !
Power is the measure of the amount of energy produced or used by a
circuit per unit of time. When current flows through a resistance, heat
is produced. This heat is the evidence that power is being used.
This is how a fuse opens, as the heat resulting from the excessive
current, melts the metal link and opens the fuse. Power is expressed in
watts or VA.
Yes that's right that 40va transformer is 40 watts VA = Volts
x Amps.

Using this formula. assume you just picked up a 40 va 24 volt
transformer and you want to fuse it what is the maximum fuse size you
should use to protect the transformer ?
E = 24 volts
I x E = 40 watts
24/40 = 1.66 amps
lets now look at a previous diagram.

- What is the value of R
- How much power is being consumed by R
answer 1 . E = I x R 6/12 = 2 ohms
answer 2 . P = I x E 12 / 6 = 72 watts
With current I through a resistance, by ohm's law the
voltage across R is equal to I x R .

What is the current in this diagram ?
I = 1 A, 4+6 = 10, 10/10 = 1
Now Vt (Voltage total) = 10 Volts and this is being applied across
Rt ( resistance total ) of 10 ohms therefore I is 1 amp.
Now that we know the current is flowing through the circuit We can
calculate the voltage drop across each resistor buy applying ohm's law.
V1 = I x R1 , 1amp x 4 ohms = 4V
Voltage drop of 4 volts from A to B
V2 = I x R2 , 1amp x 6 ohms = 6 V Voltage
drop of 6 volts from B to C
Total voltage drop 10 V
The IR voltage across each resistance is called
voltage drop the total of all combined voltage drops will always match
the exact supply voltage.
Todd Legere
April 1 2000